2.34x^2+32x+3=0

Solution for 2.34x^2+32x+3=0 equation:

2.34x^2+32x+3=0

a = 2.34; b = 32; c = +3;
Δ = b2-4ac
Δ = 322-4·2.34·3
Δ = 995.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-\sqrt{995.92}}{2*2.34}=\frac{-32-\sqrt{995.92}}{4.68}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+\sqrt{995.92}}{2*2.34}=\frac{-32+\sqrt{995.92}}{4.68}
$